| Author | Message | ||
     Drheathenscum |
anyone here run into this and how did you fix it? did you add a load equalizer or replace the flasher unit? If you replaced the flasher, what flasher did you use? If you used a load equalizer, which one did you use? I made my own load equalizer, but I'm not liking doing it that way and would really like to hear if anyone had success replacing the flasher. My biggest problem is that the bike is 2000 miles away and I can't fiddle with it to see what works. Anyone? | ||
| Spyder12s |
I used a pair of 10 ohm resistors,in series,one for each side, they did the trick. just make sure that they are rated high enough on the wattage end. edited by spyder12s on April 02, 2004 | ||
| Drheathenscum |
yeah, that's about the way I've been doing it so far... I'm trying to find a better way. thanks! | ||
| Reepicheep |
You could do better with the wiring the resistors in parallel to the bulb. Let me make some back of the envelope calculations... Assuming a normal blinker bulb is 15 watts, that would be 12v * X amps = 15 watts, which would come out to approximately 1 amp (to make the math easy). Now we gotta figure out what your LED's draw. This is a wild guess, but I would expect they pull 200 to 500 milliamps (.5 amps to make the math easy). So you gotta draw enough more current to hit the other half an amp (6 watts). You should be able to find 5 watt resistors at radio shack. If you use my approach described below (get 3 or 4 resistors rated for 5 watts and 100 ohms) that should be plenty. Careful where you put them, a full 5 watts on one resistor is plenty enough to melt plastic. Anyway, to draw about 5 watts of current on a 12 volt system, you need (12V * 12V) / X ohms = 5, or about 28 ohms. So you can validate all my above assumptions (that a turn signal bulb is 15 watts and that your LED signals draw about 500 milliamps), or just go buy a few resistors and test. If it were me, I would go get four 100 ohm or so 5 watt rated resistors. One wired in parallel to the bulb would be 100 ohms, two wired in parallel to the bulb would be 50 ohms, three wired in parallel to the bulb would be 33 ohms. One if those three combos oughta do ya, start with just one first. Putting them in series will dim the LED's, you don't want to do that. Put them in parallel (but make sure they can handle the wattage). | ||
| Dyna |
I just used a load equalizer. It also turned my rear turn signals into extra brakelights as well. Between that & the Backoff unit that makes em flash, the rear of my bike lights up like a christmas tree now. | ||
| Drheathenscum |
so, nobody has changed the flasher module? btw, I have been wiring the resistors in parallel, not series. | ||
| Dyna |
I dont believe there is a separate flasher module. Could be wrong tho. I know the HD lineup doesnt use them. | ||
| Spyder12s |
yeah you guys sorry I meant Parallel... | ||
| Stefan_f |
Hi, there is a simple solution. I posted it at the german XB-board: http://www.xborgforum.de/forum/album_pic.php?pic_id=468 Replace the marked resistor with a 0,1 Ohm / 2 Watt - that`s it! Stefan | ||
| Trojan |
We sell a new module that solves the problem. It is made by Hella and works from 10W to 200W. I think it was initially made for those strange types who like to add all sorts of tacky running lights to their Hogs & Wings. They should be available from Hella in the US but if not we can send them over. They cost around US$25 each. Part number is 4 AZ 003 787-001 |
